Time – a mental construct or a physical reality?
Posted by khuram on January 5, 2009
If we go deeper than our (actually my) understanding abilities, then we are at the level of an idealist. At this level, we are not confirmed whether material world really exists or not. Then we can theorize that time is just a mental construct.
But if we are not at this much level of depth, then we are at the level of a scientist who takes material world a reality.
At this level … time is not any physical thing. But however, time is the name of a physical phenomenon.
Physical events do occur before and after one another. Course of occurrence of physical events is a physical phenomena.
Some events are repetitive in nature and they occur at regular intervals. In normal conditions, regular interval between one kind of physical event can correspond to exact number of intervals between some other regular type physical event.
Time can only be measured by comparing the number of intervals of different regular type events.
Time is duration between events. Duration is measurable by comparing the number of intervals of different regular type events. And that physical duration is the time!
Joe Nahhas said
Kepler (demolish)Vs Einstein’s space jail of time
r ————– Exp (i wt) ———–S= r Exp (ì wt)
Nahhas’ Equation
Orbit location—-Orbit light sensing —–Visual orbit location
Particle/Newton ——Visual ————– Wave/Quantum
Quantum – Newton=visual effects=relativistic effects
=space-time confusions
S= visual distance; r = actual distance; v = speed and c = light speed
S = r Exp (i wt) = r [cosine (wt) + î sine (wt)]
P =d S/d t = v Exp (ì w t) + ì r w Exp (ì w t); v=d r/d t; v=w r
= v (1+ ì) [Exp (ì wt)] = visual velocity
E (definition) = m/2(m v + m’ r) ²; E = mc²/2 If v = 0; m’ r=mc
E (visual) = mp²/2 = mv²/2(1+ì) ² Exp 2(ì w t)
E (visual) = mv²/2(1 + 2ì -1) [cos2wt + ì sin2wt]
E (visual) = ì (mv²) [1-2sin²wt + 2i [sin (wt)] [cosine (wt)]
If wt = (2n+1) π/4
E (visual) = ì (mv²) [1-1 ± ỉ] = ± (mc²); v = c
2-Central force law Areal velocity is constant: r² (d θ/d t) =h Kepler’s Law
h = 2π a b/T; b=a√ (1-ε²); a = mean distance value; ε = eccentricity
r² (d θ/d t) = h = S² (d w/d t)
Replace r with S = r exp (ỉ wt); h = [r² Exp (2iwt)] (d w/d t)
(d w/d t) = (h/r²) exp [-2(i wt)]
d w/d t= (h/r²) [cosine 2(wt) - ỉ sine 2(wt)] = (h/r²) [1- 2sine² (wt) - ỉ sin 2(wt)]
d w/d t = d w(x)/d t + d w(y)/d t; d w(x)/d t = (h/r²) [ 1- 2sine² (wt)]
d w(x)/d t – (h/r²) = – 2(h/r²)sine²(wt) = – 2(h/r²)(v/c)² v/c=sine wt
(h/ r²)(Perihelion/Periastron)= [2πa.a√ (1-ε²)]/Ta² (1-ε) ²= [2π√ (1-ε²)]/T (1-ε) ²
Δ w/d t = (d w/d t – h/r²] = -4π {[√ (1-ε²)]/T (1-ε) ²} (v/c) ² radian per second
Δ w/d t = (- 4π /T) {[√ (1-ε²)]/ (1-ε) ²} (v/c) ² radians
Δ w°/d t = (-720/T) {[√ (1-ε²)]/ (1-ε) ²} (v/c) ² degrees; Multiplication by 180/π
Δ w°/d t = (-720×36526/T) {[√ (1-ε²)]/(1-ε)²} (v/c)² degrees/100 years
Δ w”/d t = (-720×3600/T) {[√ (1-ε²)]/(1-ε) ²} (v/c) ² seconds of arc multiplication by 3600
Δ w/d t = (-720×36526x3600/T) {[√ (1-ε²]/(1-ε)²} (v/c)² seconds of arc per century
The circumference of an ellipse: 2πa (1 – ε²/4 + 3/16(ε²)²- –.) ≈ 2πa (1-ε²/4); R =a (1-ε²/4) v=√ [G m M / (m + M) a (1-ε²/4)] ≈ √ [GM/a (1-ε²/4)]; m<<M; Solar system
Application 3: Advance of Perihelion of mercury.
G=6.673×10^-11; M=2×10^30kg; m=.32×10^24kg
ε = 0.206; T=88days; c = 299792.458 km/sec; a = 58.2km/sec
Calculations yields:
v =48.14km/sec
[√ (1- ε²)] (1-ε) ² = 1.552
Δ w”= (-720×36526x3600/88) x (1.552) (48.14/299792)²=43.0”/century
Conclusions:
E ≠ mc² (special-relativity) and the 43" seconds of arc of advance of perihelion of Planet mercury (general-relativity) is are caused by deformed space-time physicists "thought" and not deformed space (x, y, z).
Anyone dare to prove me wrong?
E=mc²/2
E (Energy by definition) = mv²/2 = mc²/2; if v = c
m = mass; v= speed; c= light speed; w= angular velocity; t= time
S = r Exp (ì w t) = r [cos (wt) + ì sin (wt)] Visual effects
P = visual velocity = change of visual location
P = d S/d t = v Exp (ì w t) + ì w r Exp (ì w t)
= (v + ì w r) Exp (ì w t) = v (1 + ì) Exp (ì w t) = visual speed; v = w r
E (visual energy= what you see in lab) = m p²/2; replace v by p in E = mv²/2
= m p²/2 = m v²/2 (1 + ì) ² Exp (2ì wt)
= mv²/2 (2ì) [cosine (2wt) + ì sine (2wt)]
=ì mv² [1 - 2 sine² (wt) + 2 ì sine (wt) cosine (wt)];v = speed; c = light speed
wt = π/2
E (visual) = ìmv² (1 – 2 + 0)
E (visual) = -ì mc² ≡ mc² (absolute value;-ì = negative complex unit) If v = c
w t = π/4
E (visual) = imv² [1-1 +ỉ] =-mc²; v = c
wt =-π/4+ỉln2/2; 2ỉ wt=-ỉπ/2 – ln2
Exp (2i wt) = Exp [-ỉπ/2] Exp [ln(1/2)]=[-ỉ (1/2)]
E (visual) = imv² (-ỉ/2) =1/2mc² v = c
Conclusion: E = mc² is the visual Illusion of E = mc²/2 joenahhas1958@yahoo.com. All rights reserved.
PS: In case of E=mc² claims to be rest energy claims then
E=1/2m (m v + m’ r) ² = (1/2m) (m’ r) ²; v = 0
E = (1/2m) (mc) ²; m’ r =mc
E=mc²/2
Alexander said
Einstein’s Physics Dollar Store on Campus
MIT Harvard Cal-Tech
Sponsored by NASA
Why Relativity theory is not Physics and why Einstein’s “thought” = 0
Walking the walk and talking the talk taking on all space-time confusion of physics by
MIT Harvard and Cal-Tech and all other Physics dollar stores departments
And why LHC burned itself
Visual Effects and the confusions of “Modern” physics
r ——— Light sensing of moving objects ——- S
Actual object—– Light ——— Visual object
r – ——-cosine (wt) + i sine (wt) – S = r [cosine (wt) + i sine (wt)]
Newton– Kepler’s time visual effects — Time dependent Newton
Particle ————– Visual effects ——————– Wave
Line of Sight: r cosine wt
r ——————- r cosine (wt) line of sight light aberrations
A moving object with velocity v will be visualized by
light sensing through an angle (wt);w = constant and t= time
Also, sine wt = v/c; cosine wt = √ [1-sine² (wt) = √ [1-(v/c) ²]
A visual object moving with velocity v will be seen as S
S = r [cosine (wt) + i sine (wt)] = r Exp [i wt]; Exp = Exponential
S = r [√ [1-(v/c) ²] + ỉ (v/c)] = S x + i S y
S x = Visual along the line of sight = r [√ [1-(v/c) ²]
This Equation is special relativity length contraction formula
And it is just the visual effects caused by light aberrations of a
moving object along the line of sight.
In a right angled velocity triangle A B C: Angle A = wt; angle B = 90°; Angle C = 90° -wt
AB = hypotenuse = c; BC = opposite = v; CA= adjacent = c √ [1-(v/c) ²]